Depreciation Fund Method: Under this method the fixed amount is credited
to depreciation fund a/c and that amount is charged from Profit & Loss
account as depreciation. The equal amount is invested in outside securities
(gilt-edge security) and the interest earn from it is reinvested in securities.
When the life of asset is over at that time the securities are sold out and
money is realised to purchase new asset. This method is also known as Sinking Fund Method and with the help of sinking fund table we can find out
the depreciation amount.
Revaluation method:
Under this method the assets are valued at the end of the year and if the value decreases then the difference between the current year asset value and previous year asset value is treated as depreciation amount. This method is applicable on patent, trademark, copyright, loose tools and live stock etc.
Example:
In January 1st 2009
Company was purchased a machine for Rs.70, 000. The estimated life of asset is
4 years. Company had decided to charge depreciation @ 5% by using sinking fund
method. On 2012 machine was sold out at
Rs.51, 100. Prepare depreciation fund a/c and depreciation fund investment a/c.
Solution:
depreciation = 0.232012*70,000
= Rs.16, 240.84
Depreciation Fund A/c
Date
|
Particular
|
J.F
|
Amount
|
Date
|
Particular
|
J.F
|
Amount
|
Dec 31,
2009
|
To balance c/d
|
16,
240.84
|
Dec
31,
2009
|
By depreciation a/c
|
16,
240.84
|
||
16,
240.84
|
16,
240.84
|
||||||
Dec 31,
2010
|
To balance c/d
|
33, 293.72
|
Jan 1,
2010
|
By balance b/d
|
16,
240.84
|
||
Dec
31,
|
By interest
(depreciation fund investment a/c)
|
812.04
|
|||||
Dec 31
|
By depreciation a/c
|
16,240.84
|
|||||
33, 293.72
|
33, 293.72
|
||||||
Dec
31,
2011
|
To balance c/d
|
51, 199.25
|
Jan 1,
2011
|
By balance b/d
|
33, 293.72
|
||
Dec
31,
|
By interest a/c
|
1, 664.69
|
|||||
Dec
31,
|
By depreciation a/c
|
16, 240.84
|
|||||
51, 199.25
|
51, 199.25
|
||||||
Dec 31, 2012
|
To machine a/c (transfer machine a/c)
|
70, 000
|
Jan 1, 2012
|
By balance b/d
|
51, 199.25
|
||
Dec 31,
|
To depreciation fund a/c
(Loss transferred)
|
99.25
|
Dec 31,
|
By interest a/c
|
2, 559.96
|
||
Dec 31,
|
By depreciation a/c
|
16, 240.84
|
|||||
Dec 31,
|
By Profit & Loss a/c (balance transfer to profit &
loss a/c)
|
99.2
|
Depreciation fund Investment
a/c
Date
|
Particular
|
J.F
|
Amount
|
Date
|
Particular
|
J.F
|
Amount
|
Dec 31,
2009
|
To bank a/c
|
16,
240.84
|
Dec
31,
2009
|
By balance c/d
|
16,
240.84
|
||
16,
240.84
|
16,
240.84
|
||||||
Jan 1,
2010
|
To balance b/d
|
16, 240.84
|
Dec 31,
2010
|
By balance c/d
|
33,
293.72
|
||
Dec
31
|
To bank a/c
|
17, 052.88
|
|||||
33, 293.72
|
33, 293.72
|
||||||
Jan 1,
2011
|
To balance b/d
|
33, 293.72
|
Dec 31,
2011
|
By balance c/d
|
51, 199.25
|
||
Dec 31
|
To bank a/c
|
17, 905.53
|
|||||
51, 199.25
|
51, 199.25
|
||||||
Jan 1, 2012
|
To balance b/d
|
51, 199.25
|
Dec
31, 2012
|
By bank a/c
|
51, 100
|
||
Dec 31,
|
By depreciation fund a/c
|
99.25
|
|||||
51, 199.25
|
51, 199.25
|
Revaluation method:
Under this method the assets are valued at the end of the year and if the value decreases then the difference between the current year asset value and previous year asset value is treated as depreciation amount. This method is applicable on patent, trademark, copyright, loose tools and live stock etc.
Depletion Unit Method: It is applicable on
wasting assets or non-current or assets or natural resources like quarries,
mines etc.
Formula:
(Original
cost of asset*Output of one year) / Total expected quantity in asset
Insurance
Policy Method: It is similar to
depreciation fund method but instead of investing money in outside securities,
the money is invested in endowment policy and depreciation amount is treated as
premium which is paid to insurance company every year. When the policy matures,
the money is received and from that money old assets are replaced by new one. In
this method depreciation a/c and insurance policy a/c are prepared but they do
not include interest.
Sum of
the years’ Digits Method:
Formula:
Cost
of asset-Scrap Value*(Estimated life of asset/ Number of years in descending
order
Example: Company purchases machinery
at the cost of Rs.90, 000 and the scrap value is Rs.12, 500. The estimated life
of asset is 6 years. Find out the depreciation amount in 2 years.
Solution: Cost of asset-Scrap Value*(Estimated life of asset/ Number of years
in descending order
Depreciation
in 1st year = (90, 000 – 12, 500)*6 / 6+5+4+3+2+1
=
77, 500 * 6 / 21
=
Rs.22, 142.86
Depreciation in 2nd
year = 77, 500 * 5/21
=
Rs. 18, 452.38
Machine
Hour Method: Under this method
scrap value is deducted from cost of machine and then divides from estimated
life of machine in hour. After then multiply with number of hours machine would
run in year.
Formula:
[(Cost
of machine – Scrap value) / Estimated life of machine (in hours)] * Number of
hours machine run in year
Example:
Company purchases machinery at the cost of Rs.85, 000 scrap value already deducted.
The estimated life of machinery is 26,000 hrs. The machine has run 1, 600 hrs in
1st year. Find out the depreciation in 1st year.
Solution:
Depreciation = [85, 000/ 26,000]* 1, 600
= Rs. 5, 230.77
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